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Maximal value of m such that 11^m <= n! : a(n) = floor( log(n!) / log(11) ).
10

%I #4 Sep 04 2015 10:24:34

%S 0,0,0,1,1,2,3,4,5,6,7,8,9,10,11,12,13,15,16,17,18,20,21,22,24,25,26,

%T 28,29,31,32,34,35,36,38,39,41,42,44,46,47,49,50,52,53,55,57,58,60,61,

%U 63,65,66,68,70,71,73,75,76,78

%N Maximal value of m such that 11^m <= n! : a(n) = floor( log(n!) / log(11) ).

%o (PARI) a(n)=lngamma(n+1)\log(11) \\ _Charles R Greathouse IV_, Sep 04 2015

%o (PARI) a(n)=logint(n!,11) \\ _Charles R Greathouse IV_, Sep 04 2015

%Y Cf. A067850, A127031, A127032, A127033, A127034, A127035, A127036, A127037, A127039.

%K nonn

%O 1,6

%A _Artur Jasinski_, Jan 03 2007