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A123375
Least k such that the difference between consecutive semiprimes A065516(k) equals n, or 0 if no such k exists.
6
3, 1, 2, 4, 24, 6, 10, 56, 50, 78, 34, 320, 249, 186, 463, 762, 598, 1238, 422, 760, 3760, 3585, 9214, 1765, 4112, 13447, 6675, 4585, 68498, 8112, 10083, 8650, 86203, 49433, 35085, 20641, 458421, 8861, 366314, 157857, 169147, 487115, 277440, 563951, 511757, 920602, 75150
OFFSET
1,1
COMMENTS
a(n) equals least k such that A065516(k) = n, or 0 if no such k exists. Conjecture: a(n)>0 exists for all n.
LINKS
Eric Weisstein's World of Mathematics, Semiprime
EXAMPLE
A065516(n) begins {2, 3, 1, 4, 1, 6, 1, 3, 1, 7, 1, 1, 3, 1, 7, 3, 2, 4, 2, 1, 4, 3, 4, 5, ...}.
Thus a(1) = 3, a(2) = 1, a(3) = 2, a(4) = 4, a(5) = 24.
MAPLE
nextSprime := proc(n) local res ; res := n+1 ; while numtheory[bigomega](res) <> 2 do res := res+1 ; od ; RETURN(res) ; end ; nmax := 500 ; kmax := 500000 ; a := array(1..nmax) ; for i from 1 to nmax do a[i] := 0 ; od : sp1 := 4 : sp2 := nextSprime(sp1) : n := sp2-sp1 : a[n] := 1 : for k from 2 to kmax do sp1 := sp2 ; sp2 := nextSprime(sp1) ; n := sp2-sp1 ; if a[n] = 0 then a[n] := k ; fi ; od : for i from 1 to nmax do if a[i] = 0 then break ; else printf("%d, ", a[i]) ; fi ; od : # R. J. Mathar, Jan 13 2007
MATHEMATICA
Table[k=6; While[FreeQ[b=Differences[Select[Range@k++, PrimeOmega[#]==2&]], n]];
Length@b, {n, 11}] (* Giorgos Kalogeropoulos, Apr 02 2021 *)
CROSSREFS
Cf. A001358 (semiprimes), A065516 (differences between semiprimes), A131109.
Sequence in context: A230892 A325671 A138382 * A021036 A354348 A211025
KEYWORD
nonn,hard
AUTHOR
Alexander Adamchuk, Nov 09 2006
EXTENSIONS
Corrected and extended by R. J. Mathar, Jan 13 2007
More terms from David A. Corneth, Apr 02 2021
STATUS
approved