%I
%S 1010,202,132,130,122,114,106,88,90,91,92,93,94,95,96,97,98,99
%N a(n) = 10*n in base n+1.
%C 99 is the last term that can be shown (using the digits 0 to 9), since the next term is 190 in base 10 = 9X in base 20.
%H Albert Frank, <a href="http://www.paulcooijmans.com/oth/intcont2003.html">International Contest Of Logical Sequences</a>, 20022003, Item 10
%H Albert Frank, <a href="http://www.paulcooijmans.com/oth/intcont2003ans.html">Solutions of International Contest Of Logical Sequences</a>, 20022003.
%K nonn,fini,full
%O 1,1
%A Herman Jamke (hermanjamke(AT)fastmail.fm), Oct 01 2006
