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%I #4 Mar 30 2012 18:40:03
%S 0,0,0,0,3,0,0,0,4,0,0,4,0,0,4,0,7,4,0,0,0,4,12,0,0,6,0,0,15,4,16,0,0,
%T 6,0,0,17,4,18,0,0,4,18,0,0,4,18,0,11,0,8,22,3,0,4,20,0,0,0,4,0,0,0,6,
%U 0,0,0,4,16,28,13,0,0,0,0,0,6,10,5,0,4,6,0,0,0,0,4,0,11,0,12,6,0,0,21,8,18
%N Least k>2 such that n is equal to arithmetic mean of k consecutive primes.
%K easy,nonn
%O 1,5
%A _Giovanni Teofilatto_, Sep 15 2006
%E Corrected and extended by _Ray Chandler_, Sep 25 2006
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