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A122103 Sum of the fifth powers of the first n primes. 9

%I #19 Jan 02 2023 12:30:46

%S 32,275,3400,20207,181258,552551,1972408,4448507,10884850,31395999,

%T 60025150,129369107,245225308,392233751,621578758,1039774251,

%U 1754698550,2599294851,3949419958,5753649309,7826720902,10903777301,14842817944

%N Sum of the fifth powers of the first n primes.

%C a(n) is prime for n = {66, 148, 150, 164, 174, 214, 238, 264, 312, 328, 354, 440, 516, 536, 616, 624, 724, 744, 774, 836, 940, ...} = A122125. Primes of this form are listed in A122126 = {32353461605953, 9874820441996857, 10821208357045699, ...}.

%H OEIS Wiki, <a href="https://oeis.org/wiki/Sums_of_primes_divisibility_sequences">Sums of powers of primes divisibility sequences</a>

%H V. Shevelev, <a href="http://list.seqfan.eu/oldermail/seqfan/2013-August/011512.html">Asymptotics of sum of the first n primes with a remainder term</a>

%F a(n) = sum(k = 1 .. n, prime(k)^5).

%F a(n) = 1/6*n^6*log(n)^5 + O(n^6*log(n)^4*log(log(n))). The proof is similar to proof for A007504(n) (see link of Shevelev). For a generalization, see comment in A122102. - _Vladimir Shevelev_, Aug 14 2013

%e a(2) = 275 because the first two primes are 2 and 3, the fifth powers of which are 32 and 243, and 32 + 243 = 275.

%e a(3) = 3400, because the third prime is 5, its fifth power if 3125 and 275 + 3125 = 3400.

%t Table[Sum[Prime[k]^5, {k, n}], {n, 100}]

%o (PARI) a(n)=sum(i=1,n,prime(i)) \\ _Charles R Greathouse IV_, Nov 30 2013

%Y Cf. A050997, A007504, A024450, A098999, A122102, A122125, A122126.

%K nonn,easy

%O 1,1

%A _Alexander Adamchuk_, Aug 20 2006

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Last modified April 18 20:26 EDT 2024. Contains 371781 sequences. (Running on oeis4.)