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a(1) = 2. a(n) = a(n-1) + (maximum number of distinct primes dividing any earlier terms).
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%I #9 Jan 12 2019 02:26:59

%S 2,3,4,5,6,8,10,12,14,16,18,20,22,24,26,28,30,33,36,39,42,45,48,51,54,

%T 57,60,63,66,69,72,75,78,81,84,87,90,93,96,99,102,105,108,111,114,117,

%U 120,123,126,129,132,135,138,141,144,147,150,153,156,159,162,165,168

%N a(1) = 2. a(n) = a(n-1) + (maximum number of distinct primes dividing any earlier terms).

%e 210 follows 207 in the sequence because the greatest number of distinct primes dividing any earlier terms of the sequence is 3.

%e 210 in the sequence is followed by 214 because 4 distinct primes divide 210, the first term of the sequence divisible by 4 distinct primes.

%K easy,nonn

%O 1,1

%A _Leroy Quet_, Jun 27 2006