%I #9 Jan 12 2019 02:26:59
%S 2,3,4,5,6,8,10,12,14,16,18,20,22,24,26,28,30,33,36,39,42,45,48,51,54,
%T 57,60,63,66,69,72,75,78,81,84,87,90,93,96,99,102,105,108,111,114,117,
%U 120,123,126,129,132,135,138,141,144,147,150,153,156,159,162,165,168
%N a(1) = 2. a(n) = a(n-1) + (maximum number of distinct primes dividing any earlier terms).
%e 210 follows 207 in the sequence because the greatest number of distinct primes dividing any earlier terms of the sequence is 3.
%e 210 in the sequence is followed by 214 because 4 distinct primes divide 210, the first term of the sequence divisible by 4 distinct primes.
%K easy,nonn
%O 1,1
%A _Leroy Quet_, Jun 27 2006