%N Sequence of pairs numerator(s(n)), denominator(s(n)) where s(n) is the n-th partial sum of 1/A119754(n).
%C There are only 78 terms of A119754 known and s(78) is 0.58817497337288808165551740612048298329310794973566 to 50 decimal places. What is sum(1/A119754(k),k=1..infinity)?
%F a(2n-1) = numerator(s(n)), a(2n)=denominator(s(n)), where s(n)=sum(1/A119754(k),k=1..n).
%e a(5)=327, a(6)=935 since s(3)=1/5+1/11+1/17=327/935.
%Y Cf. A119752, A119754.
%A _Walter Kehowski_, Jun 23 2006
%E This is not really a sequence. The standard OEIS convention would be to split this into two cross-referenced sequences with keyword "frac". - _N. J. A. Sloane_, Jul 22 2006