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a(1)=4; a(n)=floor((39+sum(a(1) to a(n-1)))/9).
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%I #5 Nov 21 2013 12:48:58

%S 4,4,5,5,6,7,7,8,9,10,11,12,14,15,17,19,21,23,26,29,32,35,39,44,49,54,

%T 60,67,74,82,91,102,113,125,139,155,172,191,212,236,262,291,324,360,

%U 400,444,493,548,609,677,752,835,928,1031,1146,1273,1415,1572

%N a(1)=4; a(n)=floor((39+sum(a(1) to a(n-1)))/9).

%t Module[{ll={4}},Do[AppendTo[ll,Floor[(39+Total[ll])/9]],{60}];ll] (* _Harvey P. Dale_, May 07 2012 *)

%Y Cf. A073941, A112088, A072493.

%K nonn

%O 1,1

%A _Graeme McRae_, Jun 10 2006

%E More terms from Harvey P. Dale, May 07 2012