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%I #4 Nov 05 2012 14:52:08
%S 1,1,2,5,11,21,37,67,140,341,881,2223,5292,11805,24767,49203,93312,
%T 170801,307550,564341,1114531,2493085,6336892,17433725,49041291,
%U 135933981,364835251,942294187,2340123130,5595955421,12914346267
%N Binomial transform of A119969.
%C Partial sums of A119971.
%C Appears to obey a 5-term hypergeometric recurrence with 4-degree polynomials. - _R. J. Mathar_, Nov 05 2012
%F G.f.: sum{k>=0, (x^2/(1-x)^3)^(2^k-1)}/(1-x); a(n)=sum{k=0..n, C(n,k)*A119969(k)}.
%K easy,nonn
%O 0,3
%A _Paul Barry_, Jun 01 2006
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