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%I #10 May 05 2023 01:38:39
%S 0,2,24,360,3360,31500,266112,2186184,17297280,133899480,1016158000,
%T 7596797208,56073378816,409544426200,2964295807200,21289879620000,
%U 151876184302080,1077036279535260,7597848475324800,53348055809155800,373012706986920000,2598270875886525840
%N a(n) = n^2*binomial(2*n, n)*Fibonacci(n).
%F Sum_{n>=0} a(n)/8^n = 101/(2*sqrt(10)). - _Amiram Eldar_, May 05 2023
%p [seq((n^2*binomial(2*n, n))*fib(n), n=0..25)];
%t a[n_] := n^2 * Binomial[2 n, n] * Fibonacci[n]; Array[a, 25, 0] (* _Amiram Eldar_, May 05 2023 *)
%Y Cf. A000984, A000045.
%K nonn,easy
%O 0,2
%A _Zerinvary Lajos_, Jun 09 2006
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