

A118532


Start with 1 and repeatedly reverse the digits and add 15 to get the next term.


3



1, 16, 76, 82, 43, 49, 109, 916, 634, 451, 169, 976, 694, 511, 130, 46, 79, 112, 226, 637, 751, 172, 286, 697, 811, 133, 346, 658, 871, 193, 406, 619, 931, 154, 466, 679, 991, 214, 427, 739, 952, 274, 487, 799, 1012, 2116, 6127, 7231, 1342, 2446
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OFFSET

1,2


COMMENTS

This sequence never cycles.
The plot (see the Noe link) shows 2774 terms of this sequence. It has a regular structure, which continues at higher decades.  T. D. Noe, May 10 2006


LINKS



FORMULA

This sequence never cycles. After a while, the pattern of length changes settles into an increasing pattern: 10^(4m)+3, 10^(4m+1)+3, 10^(4m+2)+12, 10^(4m+3)+12, 10^(4(m+1))+3, ... The key is that every two steps adds 15 at each end, unless there is a carry across the middle or a trailing 0. This allows many steps to be carried out in a single operation.  Martin Fuller, May 12 2006


PROG

(Haskell)
a118532 n = a118532_list !! (n1)
a118532_list = iterate ((+ 15) . a004086) 1


CROSSREFS



KEYWORD



AUTHOR



STATUS

approved



