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A118383 Unrefined Orloj clock sequences; row n sums to n. 4

%I #8 Feb 03 2018 09:14:32

%S 1,1,1,1,2,1,1,1,1,1,2,2,1,2,1,2,1,2,3,1,1,1,1,1,1,1,1,1,1,2,3,3,1,2,

%T 2,1,2,2,1,2,1,2,4,1,1,2,1,2,1,2,1,2,1,1,1,3,2,2,3,1,2,3,1,1,2,3,1,1,

%U 2,3,4,3,2,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2,4,1,4,2,1,2,3,3,1,2,3

%N Unrefined Orloj clock sequences; row n sums to n.

%C An Orloj clock sequence is a finite sequence of positive integers that, when iterated, can be grouped so that the groups sum to successive natural numbers. There is one unrefined sequence whose values sum to each n; all other Orloj clock sequences summing to n can be obtained by refining this one. Refining means splitting one or more terms into values summing to that term. (The unrefined sequence for n = 2^k*(2m-1) is the sequence for 2m-1 repeated 2^k times, but any single refinement - possible unless m = 1 - will produce an aperiodic sequence summing to n.) The Orloj clock sequence is the one summing to 15: 1,2,3,4,3,2, with a beautiful up and down pattern.

%H Wikipedia, <a href="https://en.wikipedia.org/wiki/Prague_astronomical_clock">Prague astronomical clock</a>

%F Let b(i),0<=i<k be all the residues of triangular numbers modulo n in order, with b(k)=n. The differences b(i+1)-b(i) are the sequence for n. The sequence for 2n is the sequence for n repeated.

%e For a sum of 5, we have 1,2,2, which groups as 1, 2, 2+1, 2+2, 1+2+2, 1+2+2+1, .... This could be refined by splitting the second 2, to give the sequence 1,2,1,1; note that when this is grouped, the two 1's from the refinement always wind up in the same sum.

%e The array starts:

%e 1;

%e 1, 1;

%e 1, 2;

%e 1, 1, 1, 1;

%e 1, 2, 2;

%e 1, 2, 1, 2;

%e 1, 2, 3, 1.

%o (PARI) {Orloj(n) = my(found,tri,i,last,r); found = vector(n,i,0); found[n] = 1; tri = 0; for(i = 1, if(n%2==0,n-1,n\2), tri += i; if(tri > n, tri -= n); found[tri] = 1); last = 0; r = []; for(i = 1, n, if(found[i], r = concat(r, [i-last]); last = i)); r}

%o for (n=1,10,print(Orloj(n)))

%Y Cf. A028355, A118382.

%Y Length of row n is A117484(n).

%K nonn,tabf

%O 1,5

%A _Franklin T. Adams-Watters_, Apr 26 2006

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