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A118346 Central terms of pendular triangle A118345. 6

%I #19 Mar 17 2021 22:50:59

%S 1,1,5,30,201,1445,10900,85128,682505,5585115,46461437,391743850,

%T 3340361700,28755475180,249572076200,2181469638880,19186562661273,

%U 169677521094215,1507881643936015,13458730170115778,120599648894147185

%N Central terms of pendular triangle A118345.

%C Also, g.f. A(x) = (1/x)*series_reversion of x/(1 + x*GF(A005572)), where GF(A005572) is the g.f. of A005572, which is the number of walks on cubic lattice starting and finishing on the xy plane and never going below it.

%H Seiichi Manyama, <a href="/A118346/b118346.txt">Table of n, a(n) for n = 0..1000</a>

%F G.f.: A=A(x) satisfies A = 1 - 2*x*A + 2*x*A^2 + x*A^3.

%F G.f.: A(x) = 1 + series_reversion( x/((1+x)*(1+4*x+x^2)) ).

%F G.f.: A(x) = (1/x)*series_reversion( x*(1-2*x + sqrt((1-2*x)*(1-6*x)))/(2*(1-2*x)) ).

%F For n>0: a(n) = (1/n)*Sum_{j=0..n} Sum_{i=0..n-1} ( binomial(n,j) * binomial(j,i) * binomial(n-j,2*j-n-i-1) * 5^(2*n-3*j+2*i+1) ). -_Vladimir Kruchinin_, Dec 26 2010

%t CoefficientList[1 +InverseSeries[Series[x/((1+x)*(1+4*x+x^2)), {x,0,30}]], x] (* _G. C. Greubel_, Mar 17 2021 *)

%o (PARI) {a(n) = polcoeff(serreverse( x*(1-2*x+sqrt((1-2*x)*(1-6*x)+x*O(x^n)))/(2*(1-2*x)))/x, n)}

%o (Sage)

%o def A118346_list(prec):

%o P.<x> = PowerSeriesRing(ZZ, prec)

%o return P( ( x/((1+x)*(1+4*x+x^2)) ).reverse() ).list()

%o a=A118346_list(31); [1]+a[1:] # _G. C. Greubel_, Mar 17 2021

%o (Magma)

%o R<x>:=PowerSeriesRing(Rationals(), 30);

%o [1] cat Coefficients(R!( Reversion( x/((1+x)*(1+4*x+x^2)) ) )); // _G. C. Greubel_, Mar 17 2021

%Y Cf. A118345, A118347, A118348, A118349.

%K nonn

%O 0,3

%A _Paul D. Hanna_, Apr 26 2006

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Last modified April 25 16:45 EDT 2024. Contains 371989 sequences. (Running on oeis4.)