%I #3 Feb 27 2009 03:00:00
%S 0,1,112,121,211,1111113,1111131,1111311,1113111,1131111,1311111,
%T 3111111,11111111111122,11111111111212,11111111111221,11111111112112,
%U 11111111112121,11111111112211,11111111121112,11111111121121
%N Numbers for which the product of the digits is the square root of the sum of the digits.
%e 1111113 is in the sequence because (1)the product of its digits is 1*1*1*1*1*1*3=3,(2)the sum of its digits is 1+1+1+1+1+1+3=9 and 3 is the square root of 9.
%K base,nonn
%O 1,3
%A Luc Stevens (lms022(AT)yahoo.com), Apr 13 2006
