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A117560 a(n) = n*(n^2 - 1)/2 - 1. 4
2, 11, 29, 59, 104, 167, 251, 359, 494, 659, 857, 1091, 1364, 1679, 2039, 2447, 2906, 3419, 3989, 4619, 5312, 6071, 6899, 7799, 8774, 9827, 10961, 12179, 13484, 14879, 16367, 17951, 19634, 21419, 23309, 25307, 27416, 29639, 31979, 34439, 37022 (list; graph; refs; listen; history; text; internal format)
OFFSET

2,1

COMMENTS

a(n-1) is an approximation for the lower bound of the "antimagic constant" of an antimagic square of order n. The antimagic constant here is defined as the least integer in the set of consecutive integers to which the rows, columns and diagonals of the square sum. By analogy with the magic constant. This approximation follows from the observation that (2*Sum_{k=1..n^2} k) + (m) + (m+1) <= Sum_{k=0..2*n+1} (m + k) where m is the antimagic constant for an antimagic square of order n. a(n) = A027480(n+1) - 1. Stricter bounds seem likely to exist. See A117561 for the upper bounds. Note there exist no antimagic squares of order two or three, but the values are indexed here for completeness.

LINKS

Vincenzo Librandi, Table of n, a(n) for n = 2..5000

Eric Weisstein's World of Mathematics, Antimagic Square.

Index entries for linear recurrences with constant coefficients, signature (4,-6,4,-1).

FORMULA

a(n) = n*(n^2 - 1)/2 - 1.

G.f.: x^2*(2 + 3*x - 3*x^2 + x^3)/(1-x)^4. - Colin Barker, Mar 29 2012

EXAMPLE

a(3) = 29 because the antimagic constant of an antimagic square of order 4 must be at least 29 (see comments).

MATHEMATICA

Table[n*(n^2-1)/2 - 1, {n, 2, 50}]

PROG

(Magma) [n*(n^2-1)/2 - 1: n in [2..50]]; // Vincenzo Librandi, Jun 20 2011

CROSSREFS

Cf. A117561, A050257, A049475.

Sequence in context: A046500 A062123 A345213 * A024178 A009312 A154251

Adjacent sequences: A117557 A117558 A117559 * A117561 A117562 A117563

KEYWORD

easy,nonn

AUTHOR

Joseph Biberstine (jrbibers(AT)indiana.edu), Mar 29 2006

STATUS

approved

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Last modified December 7 01:51 EST 2022. Contains 358649 sequences. (Running on oeis4.)