%I #7 Nov 21 2013 12:48:56
%S 1,4,125,252047376,1017210679182495207444253709079169646680657
%N a(1) = 1; for n>1, a(n)=(a(n-1)+1)^n.
%C There was a conjecture that this recurrence would produce the sequence A068894, but this is not the case.
%C The next term -- a(6) -- has 253 digits. [From Harvey P. Dale, Jan 17 2012]
%t RecurrenceTable[{a[1]==1,a[n]==(a[n-1]+1)^n},a,{n,6}] (* _Harvey P. Dale_, Jan 17 2012 *)
%K nonn
%O 1,2
%A _Vim Wenders_, Apr 18 2008
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