|
%I #10 Jul 15 2021 10:17:20
%S 125,132,147,162,163,167,169,176,186,188,192,197,209,215,218,222,223,
%T 237,247,258,259,269,270,273,274,275,277,284,288,294,297,301,302,309,
%U 316,332,359,361,362,377,382,390,393,396,398,401,404,407,413,419,425
%N Numbers k such that k^k contains a pandigital substring.
%e 125^125 = 12994...59(7369285104)69...8125.
%o (Python)
%o def haspan(s): return any(len(set(s[i:i+10]))==10 for i in range(len(s)-9))
%o print([m for m in range(500) if haspan(str(m**m))]) # _Michael S. Branicky_, Feb 28 2021
%Y Cf. A115933, A115934, A115935, A115936, A115937.
%K nonn,base
%O 1,1
%A _Giovanni Resta_, Feb 06 2006
|
