login
Numbers k such that (j^k + k^j) == 0 (mod k+j), j=5 case.
6

%I #18 Aug 07 2021 21:33:23

%S 1,3,5,7,14,15,19,20,21,23,25,26,35,45,50,55,65,73,95,105,115,119,120,

%T 125,145,165,185,195,215,225,245,270,275,285,295,305,325,350,365,385,

%U 405,425,435,437,465,495,525,527,545,585,595,605,620,621,645

%N Numbers k such that (j^k + k^j) == 0 (mod k+j), j=5 case.

%H Seiichi Manyama, <a href="/A114980/b114980.txt">Table of n, a(n) for n = 1..10000</a>

%o (PARI) isok(k, j=5) = (j^k+k^j) % (k+j) == 0; \\ _Michel Marcus_, Oct 10 2013

%o (PARI) isok(k, j=5) = Mod(j, k+j)^k+Mod(k, k+j)^j == 0; \\ _Michel Marcus_, Aug 07 2021

%Y Cf. A114977, A114978, A114979, A114981.

%K nonn

%O 1,2

%A _Zak Seidov_, Feb 22 2006

%E More terms from _Michel Marcus_, Oct 10 2013