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a(n) = floor(2^(1/3)*10^n)^3.
6

%I #11 Sep 17 2024 13:59:29

%S 1,1728,1953125,1995616979,1999899757799,1999995000191488,

%T 1999999762390486961,1999999762390486961000,1999999952878604157540864,

%U 1999999995738432193638080649,1999999999548194715368954025992,1999999999976792999366436309113669,1999999999995841811989967823752208984

%N a(n) = floor(2^(1/3)*10^n)^3.

%C Largest cube < 2*10^(3n).

%e a(1) = floor(2^(1/3)*10)^3 = 1728.

%t With[{c=Power[2, (3)^-1]},Table[(Floor[c 10^n])^3, {n,0,20}]] (* _Harvey P. Dale_, Mar 11 2011 *)

%Y Cf. A114761, A114762, A114763, A114764, A114765, A114766.

%K base,nonn

%O 0,2

%A _Amarnath Murthy_, Nov 17 2005

%E More terms from _Joshua Zucker_, Jan 11 2006