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%I #7 May 27 2018 20:41:31
%S 1,1,16,468,18784,932030,54321840,3611129620,268687287744,
%T 22085224470873,1986091468594160,193935237759263880,
%U 20436302307290415264,2311999369405933686648,279558778132903394262032
%N Self-convolution 8th power equals A113668, where a(n) = n*A113668(n-1) for n>=1, with a(0)=1.
%F G.f. A(x) satisfies:
%F (1) A(x) = 1 + x*d/dx[x*A(x)^8],
%F (2) [x^n] exp( x*A(x)^8 ) * (n + 1 - A(x)) = 0 for n > 0,
%F (3) [x^n] exp( n * x*A(x)^8 ) * (2 - A(x)) = 0 for n > 0. - _Paul D. Hanna_, May 27 2018
%o (PARI) {a(n)=local(A=1+x*O(x^n));for(i=1,n, A=1+x*deriv(x*A^8));polcoeff(A,n,x)}
%Y Cf. A113668, A000699, A113669, A113670, A113671, A113672, A113673.
%K nonn
%O 0,3
%A _Paul D. Hanna_, Nov 04 2005
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