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%I #5 Jun 13 2017 22:50:25
%S 1,6,39,327,3556,48659,812462,16136404,373415239,9900007028,
%T 296557405704,9921937128500,367181525916035,14906571298831661,
%U 659191947156441025,31558799717042019635,1626968083690674214906
%N Column 1 of triangle A113345, also equals column 0 of A113350^3.
%C A113345 is the matrix square of A113340.
%o (PARI) a(n)=local(A,B);A=matrix(1,1);A[1,1]=1;for(m=2,n+2,B=matrix(m,m); for(i=1,m, for(j=1,i,if(i<3 || j==i || j>m-1,B[i,j]=1,if(j==1, B[i,1]=1,B[i,j]=(A^(2*j-1))[i-j+1,1]));));A=B);(A^2)[n+2,2]
%Y Cf. A113340, A113345, A113346 (column 0), A113348 (column 2), A113349 (column 3); A113350.
%K nonn
%O 0,2
%A _Paul D. Hanna_, Nov 08 2005
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