%I #6 Jun 24 2014 01:08:37
%S 1,8,72,120,330,1584,1716,3432,12870,11440,19448,63648,50388,
%T 77520,232560,170544,245157,692208,480700,657800,1776060,
%U 1184040,1560780,4071600,2629575,3365856,8544096,5379616
%N G.f.: (116*x+28*x^2+56*x^3140*x^4+56*x^5+28*x^616*x^7+x^8)/(x^2x+1)^8.
%C Sequence is interesting because the initial terms seem to have many small factors.
%F a(n) = 2 cos(pi (n+1)/3) binomial(n+7,7). Note that 2 cos(pi (n+1)/3) is always 1, 1, 2, or 2, so this formula explains the small factors.  _Dean Hickerson_, Feb 06 2006
%K sign
%O 0,2
%A _Creighton Dement_, Dec 06 2005
