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%I #3 Oct 01 2013 17:58:21
%S 0,2,4,7,9,11,14,16,18,20,23,25,27,30,32,34,37,39,41,44,46,48,50,53,
%T 55,57,60,62,64,67,69,71,73,76,78,80,83,85,87,90,92,94,97,99,101,103,
%U 106,108,110,113,115,117,120,122,124,126,129,131,133,136,138,140,143,145
%N Floor of 10^n/Li(10^n) - 1.
%C Conjecture: The difference between successive terms is between 2 and 3.
%F Li(n) is the logarithmic integral which approximates the number of primes less than n. n Li(n) = Int dt/log(t) 2
%o (PARI) for(x=1,100,print1(floor(10.^x/Li(10^x)-1)",")) Li(x) = \ Logarithmic integral { -eint1(log(1/x)) }
%K easy,nonn
%O 1,2
%A _Cino Hilliard_, Nov 15 2005
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