|
%I #5 Jun 12 2022 06:44:56
%S 1,1,1,1,1,4,36,8,12,12,1,16,1296,15,56,14,9,16,8,156,1,4,2916,6,24,8,
%T 3,4,2,6,47,2,8,38,888,1,1,6561,2,236,2,1,268,1,2988,46,4,27,7
%N Cone C(n,m,k) read by planes and rows, for 1 <= k <= m <= n: Total Number of coverings of a k X m X n board using A110217(n,m,k) knights.
%e Cone starts:
%e 1.1...1........1..............1.................1......................
%e ..1,1.4,36....16,1296.........4,2916............1,6561.
%e ......8,12,12.15,..56,14......6,..24,8..........2,.236,.2
%e ...............9,..16,.8,156..3,...4,2,.6.......1,.268,.1,2988
%e .............................47,...2,8,38,888..46,...4,27,...7,.?
%e ..............................................127,..32,12,...?,....
%Y C(n, n, 1) = A103315(n), C(n, n, n) = A110216(n). A110218 gives number of inequivalent solutions.
%K hard,nonn,tabf
%O 1,6
%A Nikolaus Meyberg (Nikolaus.Meyberg(AT)t-online.de), Jul 17 2005
|
