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%I #7 Apr 05 2019 17:19:23
%S 11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97,143,
%T 187,202,206,209,214,218,221,226,247,253,254,262,274,278,298,299,302,
%U 303,309,314,319,321,323,326,327,334,339,341,346,358,362,377,381,382,386
%N Numbers n such that the number of digits required to write the prime factors of n is equal to the number of divisors of n.
%C 190333 has 10 divisors and 10 digits in its prime factorization. What is the next term in this sequence with more divisors and digits?
%C 2093663 has 12 divisors and 12 digits in its prime factorization. - _Harvey P. Dale_, Apr 05 2019
%C Prime factors are counted with multiplicity. - _Harvey P. Dale_, Apr 05 2019
%e 143 is a term because it takes 4 digits to write its prime factorization
%e 143=11*13 and has 4 divisors [1, 11, 13, 143].
%t ndQ[n_]:=Total[#[[2]]IntegerLength[#[[1]]]&/@FactorInteger[n]] == DivisorSigma[ 0,n]; Select[Range[2,500],ndQ]
%Y Cf. A076649.
%K base,easy,nonn
%O 1,1
%A _Jason Earls_, Jul 13 2005
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