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a(n) = (n+1)*(n+2)*(n+3)*(n+4)*(19*n^2 + 47*n + 30)/720.
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%I #12 Feb 27 2015 18:19:51

%S 1,16,100,399,1218,3108,6972,14190,26763,47476,80080,129493,202020,

%T 305592,450024,647292,911829,1260840,1714636,2296987,3035494,3961980,

%U 5112900,6529770,8259615,10355436,12876696,15889825,19468744,23695408

%N a(n) = (n+1)*(n+2)*(n+3)*(n+4)*(19*n^2 + 47*n + 30)/720.

%C Kekulé numbers for certain benzenoids.

%D S. J. Cyvin and I. Gutman, Kekulé structures in benzenoid hydrocarbons, Lecture Notes in Chemistry, No. 46, Springer, New York, 1988 (p. 231, # 41).

%F G.f.: (1 + 9*x + 9*x^2)/(1-x)^7.

%p a:=n->(n+1)*(n+2)*(n+3)*(n+4)*(19*n^2+47*n+30)/720: seq(a(n),n=0..33);

%t Table[(n+1)(n+2)(n+3)(n+4)(19n^2+47n+30)/720,{n,0,40}] (* _Harvey P. Dale_, Mar 04 2011 *)

%K nonn,easy

%O 0,2

%A _Emeric Deutsch_, Jun 17 2005