|
%I #3 Oct 01 2013 17:58:11
%S 3,5,3,5,3,5,3,5,3,5,4,4,4,4,4,4,3,5,4,5,3,4,3,5,5,4,5,3,5,4,3,3,3,3,
%T 4,4,5,5,4,5,3,4,5,4,4,5,3,4,4,4,4,4,4,5,4,4,3,3,4,3,5,3,3,5,5,3,4,4,
%U 5,3,3,5,4,5,4,5,4,4,5,4,4,4,4,5,3,5,5,3,3,5,5,4,3,4,3,3,3,4,3,5,4,3,5,4,3
%N Number of letters in the words formed by the digital recitation of e in the English language.
%o (PARI) reade(n) = { local(x,a,d); default(realprecision,200); d=vector(10); a=vector(n); d[1]=4;d[2]=3;d[3]=3;d[4]=5;d[5]=4;d[6]=4;d[7]=3;d[8]=5;d[9]=5;d[10]=4; a=Vec(Str(exp(1))); print1(3","); for(x=3,n-1, y=floor(eval(a[x])); print1(d[y+1]",") ) }
%K base,easy,nonn,word
%O 1,1
%A _Cino Hilliard_, May 28 2005 and May 31 2005
|
