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(1 + n + n^2)^n.
0

%I #4 Nov 21 2022 19:10:54

%S 1,3,49,2197,194481,28629151,6321363049,1954897493193,806460091894081,

%T 427929800129788411,283942098606901565601,230339304218442143770717,

%U 224282727500720205065439601,258145266804692077858261512663

%N (1 + n + n^2)^n.

%t Table[(1+n+n^2)^n,{n,0,15}] (* _Harvey P. Dale_, Nov 21 2022 *)

%Y Equals A002061(n+1)^n.

%K nonn

%O 1,2

%A _Ralf Stephan_, May 05 2005