%I #8 Mar 16 2020 14:02:09
%S 0,1,1,2,1,2,1,2,2,1,2,2,1,2,2,2,1,2,2,1,2,2,2,3,2,1,2,1,2,2,2,2,1,2,
%T 1,2,2,2,2,2,1,2,1,2,1,3,3,2,1,2,2,1,2,2,2,2,1,2,2,1,2,2,2,1,2,2,2,2,
%U 1,2,2,3,2,2,2,2,3,2,3,2,1
%N Number of prime factors with multiplicity of the difference between consecutive primes.
%F a(n) = bigomega(p(n+1)-p(n)).
%e p(5)-p(4)=4, bigomega(4)=2.
%t PrimeOmega/@Differences[Prime[Range[100]]] (* _Harvey P. Dale_, Mar 16 2020 *)
%o (PARI) a(n) = bigomega(prime(n+1) - prime(n)); \\ _Michel Marcus_, Aug 26 2013
%Y Cf. A001222, A001223.
%K easy,nonn
%O 1,4
%A Paul Finley (pfinley(AT)touro.edu), Sep 11 2007