%I
%S 1,2,2,2,2,2,2,4,4,4,2,2,3,3,3,4,2,4,3,5,5,4,4,5,4,4,2,4,5,4,3,4,3,5,
%T 5,3,5,5,4,4,5,5,2,3,6,4,4,8,4,4,6,3,4,6,6,5,6,5,5,3,3,7,8,5,5,3
%N Number of distinct prime divisors of 100^n  3.
%F a(n) = A001221(100^n3).
%F a(n) = A105068(2*n).  _Amiram Eldar_, Jan 25 2020
%e If n = 1, then 100^1  3 = 97 which is prime so the first term is 1.
%p A105069 := proc(n) 100^n3 ; numtheory[factorset](%) ; nops(%) ; end proc: # _R. J. Mathar_, Aug 24 2011
%t Table[PrimeNu[(100)^n  3], {n, 1, 50}] (* _G. C. Greubel_, May 07 2017 *)
%Y Cf. A001221, A105068.
%K nonn,more
%O 1,2
%A _Parthasarathy Nambi_, Apr 05 2005
%E More terms from _Amiram Eldar_, Jan 25 2020
%E a(61)a(66) from _Jinyuan Wang_, Apr 01 2020
