%I
%S 0,0,1,2,3,4,5,6,7,3,1,4,5,6,6,11,7,9,1,4,3,6,8,7,8,11,10,2,2,8,4,9,7,
%T 11,11,12,3,2,4,5,6,9,10,11,12,2,4,10,5,10,9,17,12,10,4,4,4,9,11,8,8,
%U 12,12,4,4,10,11,9,11,15,13,9,5,6,5,9,6,9,9
%N Number of prime factors, with multiplicity, of the nonzero octanacci numbers A079262.
%H Amiram Eldar, <a href="/A104415/b104415.txt">Table of n, a(n) for n = 1..262</a>
%F a(n) = A001222(A079262(n+6)).
%e a(0)=a(1)=0 because the first two nonzero octanacci numbers are both 1, which has zero prime divisors.
%e a(2)=1 because the 3rd nonzero octanacci number is 2, a prime, with only one prime divisor.
%e a(3)=2 because the 4th nonzero octanacci number is 4 = 2^2 which has (with multiplicity) 2 prime divisors (which happen to be equal).
%e a(4)=3 because the 5th nonzero octanacci number is 8 = 2^3.
%e a(10)=3 because A079262(10) = 255 = 3 * 5 * 17 which has 3 prime factors.
%Y Cf. A001222, A079262, A104411, A104412, A104413, A104414.
%K easy,nonn
%O 1,4
%A _Jonathan Vos Post_, Mar 06 2005
%E Offset corrected and more terms added by _Amiram Eldar_, Sep 08 2019
