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 A104375 Smallest prime formed by concatenation of n consecutive cubes, 0 if no such prime exists. 1
 0, 827, 0, 2744337540964913, 49135832685980009261, 0, 16194277163870641658137516777216169745931717351217373979, 64348566539203664467267512696859000696787170778887189057, 0 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS From Robert Israel, Feb 20 2020: (Start) a(n)=0 if n is divisible by 3, as the sum of three consecutive cubes is divisible by 3. a(22) has 2132 digits, too large for a b-file: it is the concatenation of 99999999999999999999999999999998^3 to 100000000000000000000000000000019^3. (End) LINKS Robert Israel, Table of n, a(n) for n = 1..21 EXAMPLE a(2)=827 because 827 is the smallest prime formed from concatenation of 2 consecutive cubes i.e. 8 and 27. MAPLE ccat:= proc(L) local t, i; t:= L[1]; for i from 2 to nops(L) do t:= t*10^(ilog10(L[i])+1)+L[i] od; t end proc: f:= proc(n) local k, p; if n mod 3 = 0 then return 0 fi; for k from floor(n/2)*2+1 by 2 do p:= ccat([seq((k-i)^3, i=n-1..0, -1)]); if isprime(p) then return p fi od end proc: f(1):= 0: map(f, [\$1..10]); # Robert Israel, Feb 20 2020 CROSSREFS Sequence in context: A237062 A251616 A251611 * A066946 A143799 A046496 Adjacent sequences: A104372 A104373 A104374 * A104376 A104377 A104378 KEYWORD base,nonn AUTHOR Shyam Sunder Gupta, Apr 17 2005 STATUS approved

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Last modified December 8 17:58 EST 2023. Contains 367680 sequences. (Running on oeis4.)