%I #6 Mar 21 2021 21:55:04

%S 2,11,211,9227465570288735245782178309

%N Smallest prime formed by reverse concatenation of n consecutive Fibonacci numbers.

%e a(3)=211 because 211 is the smallest prime formed from reverse concatenation of 3 consecutive Fibonacci numbers i.e. 1,1 and 2.

%Y Cf. A000045.

%K base,nonn

%O 1,1

%A _Shyam Sunder Gupta_, Apr 17 2005