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%I #13 Jun 18 2017 13:50:46
%S 4,12,630,117656,25937424612,23298085122494,48661191875666868498,
%T 104127350297911241532860,907846434775996175406740561352,
%U 88540901833145211536614766025207452637390
%N Integers of the form p^(p-1)+p where p is prime.
%C Sum of the reciprocals 1/a(n) rapidly converges to 0.3349291343132812638... - _R. J. Mathar_, Apr 27 2007
%F From _R. J. Mathar_, Apr 27 2007: (Start)
%F a(n) = A036878(n)+p where p=A000040(n).
%F For p>2, a(n) = p*[1+A085531(A005097(n-1))]. (End)
%Y Cf. A000040, A005097, A036878, A085531.
%K easy,nonn
%O 1,1
%A _Cino Hilliard_, Mar 06 2005
%E Edited by _R. J. Mathar_, Apr 27 2007
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