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%I #4 Mar 30 2012 18:36:44
%S 1,-7,36,-170,775,-3481,15542,-69276,308945,-1380035,6178088,
%T -27725806,124743163,-562660125,2544153290,-11530989904,52380358293,
%U -238450946439,1087698574940,-4971055063490,22760027348511,-104384818070017,479513717931486,-2206100494746180
%N Column 2 of triangle A102051, which is the matrix inverse of triangle A101275 (number of Schroeder paths).
%F G.f.: 32*(1-x)^2/(1+sqrt(1+4*x-4*x^2))^5.
%o (PARI) {a(n)=polcoeff(32*(1-x)^2/(1+sqrt(1+4*x-4*x^2))^5,n)}
%Y Cf. A101275, A102051.
%K sign
%O 0,2
%A _Paul D. Hanna_, Dec 27 2004
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