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A101378 a(n) = n^2*(n^3+1)/2. 1

%I #12 Sep 08 2022 08:45:16

%S 0,1,18,126,520,1575,3906,8428,16416,29565,50050,80586,124488,185731,

%T 269010,379800,524416,710073,944946,1238230,1600200,2042271,2577058,

%U 3218436,3981600,4883125,5941026,7174818,8605576,10255995,12150450,14315056,16777728,19568241

%N a(n) = n^2*(n^3+1)/2.

%D T. A. Gulliver, Sequences from Cubes of Integers, Int. Math. Journal, 4 (2003), 439-445.

%H Vincenzo Librandi, <a href="/A101378/b101378.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_06">Index entries for linear recurrences with constant coefficients</a>, signature (6,-15,20,-15,6,-1).

%F G.f.: x*(1 + 12*x + 33*x^2 + 14*x^3)/(1 - x)^6. - _Ilya Gutkovskiy_, Feb 24 2017

%o (Magma) [n^2*(n^3+1)/2: n in [0..40]]; // _Vincenzo Librandi_, Jun 15 2011

%o (PARI) a(n)=n^2*(n^3+1)/2 \\ _Charles R Greathouse IV_, Feb 24 2017

%K nonn,easy

%O 0,3

%A _N. J. A. Sloane_, Jan 15 2005

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Last modified April 16 01:40 EDT 2024. Contains 371696 sequences. (Running on oeis4.)