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%I #3 Mar 30 2012 18:59:02
%S 1,4,24,96,624,2496,14976,59904,390624,1562496,9374976,37499904,
%T 243749376,974997504,5849985024,23399940096,152587890624,610351562496,
%U 3662109374976,14648437499904,95214843749376,380859374997504
%N Inverse modulo 2 binomial transform of 5^n.
%C 5^n may be retrieved as sum{k=0..n, mod(binomial(n,k),2)A100738(k)}.
%F a(n)=sum{k=0..n, (-1)^A010060(n-k)*mod(binomial(n, k), 2)5^k}.
%K easy,nonn
%O 0,2
%A _Paul Barry_, Dec 06 2004
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