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A099513
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Row sums of triangle A099512, so that a(n) = Sum_{k=0..n} coefficient of z^k in (1 + 3*z + z^2)^(n-[k/2]), where [k/2] is the integer floor of k/2.
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1
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1, 4, 8, 27, 89, 257, 784, 2421, 7336, 22324, 68147, 207549, 632177, 1926608, 5870089, 17884476, 54493120, 166034731, 505883825, 1541369745, 4696373312, 14309268413, 43598614528, 132839740908, 404746601923, 1233213978037
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OFFSET
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0,2
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LINKS
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FORMULA
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G.f.: (1+2*x-x^2)/(1-2*x-x^2-7*x^3+x^4).
a(0)=1, a(1)=4, a(2)=8, a(3)=27, a(n)=2*a(n-1)+a(n-2)+7*a(n-3)- a(n-4) [From Harvey P. Dale, Jul 12 2011]
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MATHEMATICA
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LinearRecurrence[{2, 1, 7, -1}, {1, 4, 8, 27}, 30] (* or *) CoefficientList[ Series[ (1+2x-x^2)/(1-2x-x^2-7x^3+x^4), {x, 0, 30}], x] (* Harvey P. Dale, Jul 12 2011 *)
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PROG
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(PARI) a(n)=sum(k=0, n, polcoeff((1+3*x+x^2+x*O(x^k))^(n-k\2), k))
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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