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A096800 Triangle of coefficients, read by row polynomials P_n(y), that satisfy the g.f.: A096651(x,y) = Product_{n>=1} 1/(1-x^n)^[P_n(y)/n], with P_n(0)=0 for n>=1. 2

%I #3 Mar 30 2012 18:36:41

%S 1,1,1,2,0,1,2,1,0,1,4,-5,5,0,1,2,2,-5,6,0,1,6,-28,28,-7,7,0,1,4,90,

%T -136,49,-8,8,0,1,6,-738,1082,-432,90,-9,9,0,1,4,6279,-9525,4075,-969,

%U 145,-10,10,0,1,10,-66594,101915,-44803,11143,-1881,220,-11,11,0,1,4,816362,-1260268,565988,-144300,25207,-3300,318

%N Triangle of coefficients, read by row polynomials P_n(y), that satisfy the g.f.: A096651(x,y) = Product_{n>=1} 1/(1-x^n)^[P_n(y)/n], with P_n(0)=0 for n>=1.

%C Row sums form the positive integers. The first column forms the totients (A000010). The inverse Moebius transform of each column forms the columns of triangle {n/k*A096799(n,k)}. A generalized Euler transform of the row polynomials of this triangle generates A096651; the row sums of A096651^n form the n-dimensional partitions.

%e G.f.: 1/A096651(x,y) = (1-x)^y*(1-x^2)^[(y+y^2)/2]*(1-x^3)^[(2y+y^3)/3]*(1-x^4)^[(2y+y^2+y^4)/4]*(1-x^5)^[(4y-5y^2+5y^3+y^5)/5]*...

%e Rows begin:

%e [1],

%e [1,1],

%e [2,0,1],

%e [2,1,0,1],

%e [4,-5,5,0,1],

%e [2,2,-5,6,0,1],

%e [6,-28,28,-7,7,0,1],

%e [4,90,-136,49,-8,8,0,1],

%e [6,-738,1082,-432,90,-9,9,0,1],

%e [4,6279,-9525,4075,-969,145,-10,10,0,1],

%e [10,-66594,101915,-44803,11143,-1881,220,-11,11,0,1],

%e [4,816362,-1260268,565988,-144300,25207,-3300,318,-12,12,0,1],

%e [12,-11418459,17738565,-8095100,2105129,-375609,50414,-5382,442,-13,13,0,1],...

%Y Cf. A096651, A096799.

%K sign,tabl

%O 0,4

%A _Paul D. Hanna_, Jul 13 2004

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Last modified April 23 20:33 EDT 2024. Contains 371916 sequences. (Running on oeis4.)