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A095971 If p(k) is the k-th prime, then the n-th set of 4 consecutive cousin prime pairs starts at p(a(n)). 1

%I #2 Mar 31 2012 14:11:24

%S 25,147,149,1828,1866,18814,20033,26397,57344,63654,71722,72982,76928,

%T 85072,99739,110985,122244,136645,145805,166884,183130,204206,244875,

%U 246292,256139,258721,258723,263243,296747,296749,299538,336778,356245

%N If p(k) is the k-th prime, then the n-th set of 4 consecutive cousin prime pairs starts at p(a(n)).

%e a(1)=25: p(25)=97 and p(26)=101, the first cousin prime pair; p(27)=103 and p(28)=107, the second cousin prime pair; p(29)=109 and p(30)=113, the third cousin prime pair; p(31)=127 and p(32)=131, the fourth cousin prime pair.

%K nonn

%O 1,1

%A _Ray G. Opao_, Jul 15 2004

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Last modified March 29 09:42 EDT 2024. Contains 371268 sequences. (Running on oeis4.)