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a(n) = floor(n^n*log(n)).
0

%I #7 Dec 15 2017 17:36:40

%S 0,2,29,354,5029,83596,1602540,34887239,851249820,23025850929,

%T 684147506232,22155677294049,776859310044893,29325223059723664,

%U 1185838637907315360,51145234580810622639,2343748148716928136491

%N a(n) = floor(n^n*log(n)).

%t Table[Floor[n^n Log[n]],{n,20}] (* _Harvey P. Dale_, Mar 04 2013 *)

%K easy,nonn

%O 1,2

%A _Jason Earls_, Jun 19 2004