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%I #9 Oct 18 2016 05:20:15
%S 9,15,11340,278775,16247385,37139825022300,7581939039675,
%T 76731473729479944375,3915591422490399696806136375,
%U 381397512477801513050979496875,16227546388799797830522276658125
%N a(n) = numerator of Sum_{k in A030059} 1/k^(2n).
%C See the Hardy reference, p. 65, fourth formula (with a misprint corrected), and the Weisstein link, eqs. (25)-(31). - _Wolfdieter Lang_, Oct 18 2016
%D G. H. Hardy, Ramanujan, AMS Chelsea Publishing, 2002, pp. 64 - 65, (misprint on p.65, line starting with Hence: it should be ... -1/Zeta(s) not ... -Zeta(s)).
%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/PrimeSums.html">Prime Sums</a>
%F Numerator of (zeta(2n)^2-zeta(4n))/(2zeta(2n)zeta(4n)).
%e 9/(2*Pi^2), 15/(2*Pi^4), 11340/(691*Pi^6), 278775/(7234*Pi^8), ...
%Y Cf. A030059, A093596 (denominators).
%K nonn,easy,frac
%O 1,1
%A _Eric W. Weisstein_, Apr 03 2004
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