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%I #43 Oct 02 2022 23:19:09
%S 1,2,2,1,4,0,2,7,5,8,1,6,0,1,6,9,8,3,3,9,2,1,0,7,1,9,9,4,6,3,9,6,7,4,
%T 1,7,0,3,0,7,5,8,0,9,4,1,5,2,0,5,0,3,6,4,1,2,7,3,4,2,5,0,9,8,5,9,9,2,
%U 0,6,2,3,3,0,8,3,6,3,7,8,1,6,2,4,2,2,8,8,7,4,4,0,1,3,3,7,2,4,7,3,9,6,9,0,2
%N Decimal expansion of e^(1/5).
%C e^(1/5) maximizes the value of x^(c/(x^5)) for any real positive constant c, and minimizes for it for a negative constant, on the range x > 0. - _A.H.M. Smeets_, Aug 16 2018
%H G. C. Greubel, <a href="/A092514/b092514.txt">Table of n, a(n) for n = 1..5000</a>
%H <a href="/index/Tra#transcendental">Index entries for transcendental numbers</a>
%F e^(1/5) = 5^(2*5)/21355775*(1 + Sum_{n>=1} (1 + n^7/5 + n/5)/(5^n*n!)). - _Alexander R. Povolotsky_, Sep 13 2011
%F e^(1/5) = (1/2)*lim_{n -> oo} 1 + (6 + (11 + (16 + ... + ((5*n+1)/ (5*n))/...)/15)/10)/5 = lim_{n -> oo} 1 + (1 + (1 + (1 + ... + (1 + 1/(5*n+5))/(5*n)/...)/15)/10)/5. - _Rok Cestnik_, Jan 19 2017
%e 1.22140275816...
%p evalf(exp(1/5)); # _Muniru A Asiru_, Aug 16 2018
%t RealDigits[Surd[E,5],10,120][[1]] (* _Harvey P. Dale_, Aug 12 2016 *)
%o (PARI) exp(1/5) \\ _Michel Marcus_, Aug 16 2018
%o (Magma) Exp(1/5); // _Vincenzo Librandi_, Aug 17 2018
%Y Cf. A001113, A019774.
%K cons,nonn
%O 1,2
%A _Mohammad K. Azarian_, Apr 05 2004
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