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A092386 Let p(n) = n-th prime; a(n) = largest prime factor of (p(n+1)^2 - p(n)*p(n+2)). 1

%I #9 Aug 24 2017 13:41:13

%S 1,2,3,5,3,7,5,11,2,7,7,5,13,7,3,31,29,79,5,7,13,71,13,7,7,11,37,7,

%T 179,17,17,7,13,101,37,3,7,31,3,13,17,43,7,67,983,3,229,11,5,17,11,53,

%U 19,3,3,17,67,17,19,17,43,521,7,103,173,683,23,233,23,31,67,23,3,23,53,73,5

%N Let p(n) = n-th prime; a(n) = largest prime factor of (p(n+1)^2 - p(n)*p(n+2)).

%H Ivan Neretin, <a href="/A092386/b092386.txt">Table of n, a(n) for n = 0..9999</a>

%F a(n) = A006530(A056221(n)).

%t Table[ FactorInteger[Prime[n + 1]^2 - Prime[n]Prime[n + 2]][[ -1, 1]], {n, 80}] (* _Robert G. Wilson v_, Mar 24 2004 *)

%Y Cf. A006530, A056221.

%K easy,nonn

%O 0,2

%A Frank Schwellinger (nummer_eins(AT)web.de), Mar 20 2004

%E More terms from _Robert G. Wilson v_, Mar 24 2004

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Last modified April 16 07:57 EDT 2024. Contains 371698 sequences. (Running on oeis4.)