%I #3 Mar 30 2012 18:36:40
%S 2,6,7,8,9,9,11,11,12,11,12,14,13,13,13,13,14,13,13,14,15,14,14,14,14,
%T 15,14,15,15,15,16,16,16,17,15,16,16,16,17,15,17,17,17,16,16,17,17,17,
%U 17,17,17,17,18,16,19,17,19,18,17,17,18,18,18,18,18,18,19,19,18,19,18
%N a(n) equals the maximum number of partial quotients in the simple continued fraction expansion of (1/n + 1/k) for k>=1.
%F a(n) = length(contfrac(1/A091941(n) + 1/n)).
%o (PARI) {a(n)=local(A);M=0;for(k=2*n^2-1,3*n^2, L=length(contfrac(1/k+1/n));if(L>M,M=L;A=M));A}
%Y Cf. A091941, A091943, A091944.
%K nonn
%O 1,1
%A _Paul D. Hanna_, Feb 15 2004
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