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a(n) = (Fibonacci(2n+1) + Fibonacci(2n+2)*phi)/kappa(phi/Fibonacci(4n+2)) where kappa(x) is the sum of successive remainders by computing the Euclidean algorithm for (1,x).
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%I #10 Oct 11 2017 05:13:26

%S 1,32,605,10933,196384,3524489,63245753,1134902560,20365009477,

%T 365435291981,6557470308896,117669030432337,2111485077903025,

%U 37889062372947488,679891637638098029,12200160415120530469

%N a(n) = (Fibonacci(2n+1) + Fibonacci(2n+2)*phi)/kappa(phi/Fibonacci(4n+2)) where kappa(x) is the sum of successive remainders by computing the Euclidean algorithm for (1,x).

%K easy,nonn

%O 0,2

%A _Thomas Baruchel_, Nov 29 2003; corrected Jun 09 2004