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Permanent of the character table of the symmetric group S_n.
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%I #11 Dec 08 2014 15:51:48

%S 1,0,0,0,0,0,0,-20834715303936,602706855887546351616

%N Permanent of the character table of the symmetric group S_n.

%C In the Schmidt-Simion reference it is proved that if A000701(n) is odd then a(n) = 0. So a(11)=a(12)=a(13)=0. The computation of a(10) involves a permanent of dimension 42, and it may take a long time for GAP to compute it.

%H F. W. Schmidt and R. Simion, <a href="http://dx.doi.org/10.1016/0097-3165(84)90012-8">On a partition identity</a>, J. Combin. Theory, A 36 (1984), 249-252.

%o (GAP) Permanent(Irr(SymmetricGroup(n)));

%Y Cf. A007870.

%K sign,more

%O 1,8

%A Yuval Dekel (dekelyuval(AT)hotmail.com), Jul 26 2003

%E a(9) from _Ferenc Szollosi_, Jul 25 2014