|
%I #13 Mar 07 2013 20:34:45
%S 0,1,0,0,1,0,1,0,0,1,0,1,0,0,1,0,0,1,0,1,0,0,1,0,1,0,0,1,0,0,1,0,1,0,
%T 0,1,0,1,0,0,1,0,1,0,0,1,0,0,1,0,1,0,0,1,0,1,0,0,1,0,0,1,0,1,0,0,1,0,
%U 1,0,0,1,0,1,0,0,1,0,0,1,0,1,0,0,1,0,1,0,0,1,0,0,1,0,1,0,0,1,0,1,0,0
%N a(n) = A085239(n) - 2.
%C First 42 terms coincide with a(1)..a(42) of A212126 which is a periodic sequence. - _Omar E. Pol_, Mar 01 2013
%K nonn
%O 1,1
%A _Reinhard Zumkeller_, Jun 22 2003
|
