%I #4 Dec 05 2013 19:56:18
%S 1,2,9,10,81,244,4826809,24134046,258867666103225,517735332206451
%N a(1) =1, then the smallest number a(n)== 1 ( mod a(n-1)) such that tau(a(n))= n.
%C a(11) = (2*a(10)-1)^10, which is about 1.4*10^150, too large to include. - _David Wasserman_, Jan 20 2005
%e a(4) = 10, a(5) = 81 == 1 (mod 10) and tau(81) = 5.
%Y Cf. A085070.
%K nonn
%O 1,2
%A _Amarnath Murthy_, Jun 30 2003
%E More terms from _David Wasserman_, Jan 20 2005