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A084839 Smallest integers that satisfy sum(n>0, mu(a(n))*log(a(n))/a(n))=-1 by requiring that the absolute values of 1 + the successive partial sums are monotonically decreasing in magnitude, where a(1)=1 and a(n+1)>a(n) for n>0. 1

%I #4 Mar 30 2012 18:36:38

%S 1,2,3,5,62,66,69,73,77,83,87,89,91,97,106,110,111,113,115,127,142,

%T 149,158,163,166,167,177,190,194,197,201,211,221,223,226,229,235,246,

%U 253,255,259,266,274,281,287,293,295,307,321,331,341,345,355,366,371,373

%N Smallest integers that satisfy sum(n>0, mu(a(n))*log(a(n))/a(n))=-1 by requiring that the absolute values of 1 + the successive partial sums are monotonically decreasing in magnitude, where a(1)=1 and a(n+1)>a(n) for n>0.

%C Since sum(n>0,mu(n)*log(n)/n)=-1, this sequence gives a subset of integers that satisfy this sum.

%o (PARI) S=0; a=0; w=2; for(n=1,200,b=a+1; while(abs(S+moebius(b)*log(b)/b+1)>=w,b++); S=S+moebius(b)*log(b)/b; w=abs(S+1); a=b; print1(b,","))

%Y Cf. A084838.

%K nonn

%O 1,2

%A _Paul D. Hanna_, Jun 06 2003

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